Count character length, and shorten only if too long?

Bobbo Jones · 2013-01-23 06:08

Hi all, I searched on this topic and did not find any work around advice, although i did find a thread stating a similar problem with no replies.

I need to be able to count file name characters, and when they pass 25 characters, to remove the first characters leaving a maximum of only 25 characters. Is it possible to do this with this program?
thanks

Bobbo

Stefan · 2013-01-23 06:18

Bobbo Jones wrote:

Hi all, I searched on this topic and did not find any work around advice, although i did find a thread stating a similar problem with no replies.
I need to be able to count file name characters, and when they pass 25 characters, to remove the first characters leaving a maximum of only 25 characters. Is it possible to do this with this program?
thanks
Bobbo

Hi, welcome.

FROM:
ABCDEFGHIJKLMNOPQRSTUVWXYZ123456789

TO:
KLMNOPQRSTUVWXYZ123456789

USE:
Delete Rule: Delete from Position 26 until the End (right-to-left) (skip extension)

.

Bobbo Jones · 2013-01-23 06:22

Pretty cool program you have here. Once you wrote that it made immediate sense. Thanks so much! Only problem is I never saw a donate tab anywhere!

Stefan · 2013-01-23 06:52

Bobbo Jones wrote:

Only problem is I never saw a donate tab anywhere!

Please note my signature

.

Bobbo Jones · 2013-03-07 00:46

What if I want to do the same as above, but retain the first 4 characters as well? ie the goal is (in brackets deleted)
1234(567890ABCD)EFGHIJKLMNOPQRSTUVWYZ

is this possible?

Stefan · 2013-03-07 07:52

Hi and welcome BJ!

Bobbo Jones wrote:

What if I want to do the same as above, but retain the first 4 characters as well?
ie the goal is (in brackets deleted)
1234(567890ABCD)EFGHIJKLMNOPQRSTUVWYZ
is this possible?

"in brackets deleted"
FROM:
1234(567890ABCD)EFGHIJKLMNOPQRSTUVWYZ
TO:
1234()EFGHIJKLMNOPQRSTUVWYZ
USE:
Rearrange Rule: Split by delimiters "(|)", New pattern "$1()$3" (skip extension)

But one would think you would rather think about something like this:

"deleted brackets and all in between"
FROM:
1234(567890ABCD)EFGHIJKLMNOPQRSTUVWYZ
TO:
1234EFGHIJKLMNOPQRSTUVWYZ
USE:
CleanUp Rule: Strip out contents of brackets (..) , Fix spaces (skip extension) This option removes the brackets also.

HTH?
see our wiki for more:
http://www.den4b.com/wiki/ReNamer:Rules
.

Bobo Jones · 2013-03-07 11:53

it seems you cannot log in on more than 1 computer at once. I stayed logged in and left my computer running at work, now Im home on another computer and had to create a new login.

ANyway,

WOOPS!!! my explanation was bad, the brackets don't actually exist! they are there for the example only....

Stefan · 2013-03-07 12:44

Bobo Jones wrote:

it seems you cannot log in on more than 1 computer at once.
I stayed logged in and left my computer running at work, now Im home on another computer and had to create a new login.

That should not be a issue. I been always logged-in at the same time on different computers.

ANyway,
WOOPS!!! my explanation was bad, the brackets don't actually exist! they are there for the example only....

*sigh*

Still not clear!
Please provide some real life example of names as they are now and how they should look after the renaming.

For example:

FROM:
1234567890ABCDEFGHIJKLMNOPQRSTUVWYZ
TO:
1234EFGHIJKLMNOPQRSTUVWYZ

What does that means?

You want to delete from fifth sign till 14?
IOTW, You want to delete 10 signs from starting at fifth sign?
1) Delete: Delete from Position 5 until Count reaches 10 (skip extension)

Or you want to keep first four signs AND also 21 last signs (counting from the right)
and delete between, no matter how many signs?
1) Insert: Insert "#" at Position 22 (right-to-left) (skip extension)
2) Delete: Delete from Position 5 until Delimiter "#" (skip extension)

Or is there another possibility?
Maybe: delete from fifth sign till "E"
1) Delete: Delete from Position 5 until Delimiter "E" (skip extension)(leave delimiter)

Please be more clear what you are after. Thank you.

Bobbo Jones · 2013-03-08 00:30

*Sigh* back atcha,

I need to be able to count file name characters, and when they pass 25 characters, to remove the first characters leaving a maximum of only 25 characters.

What if I want to do the same as above, but retain the first 4 characters as well?

Thanks though! option 2 that you provided gives me what I need to construct the solution.

I've done
Insert "#" at Position 5 (skip extension)
Delete from Position 25 until Delimiter "#" (Right to left) (Skip Extension)(leave delimiter)
Remove all "#" (Skip Extension)

Cheers thanks again

SafetyCar · 2013-03-08 21:05

Another option would have been with:

RegEx: Replace expression "^(.{4})(.*)(.{21})$" with "$1$3"

Skipping extension depends if you want to count the chars of the extension or not. If you want to have strictly 25 chars you should NOT skip it.

den4b Forum

#1 2013-01-23 06:08

Count character length, and shorten only if too long?

#2 2013-01-23 06:18

Re: Count character length, and shorten only if too long?

#3 2013-01-23 06:22

Re: Count character length, and shorten only if too long?

#4 2013-01-23 06:52

Re: Count character length, and shorten only if too long?

#5 2013-03-07 00:46

Re: Count character length, and shorten only if too long?

#6 2013-03-07 07:52

Re: Count character length, and shorten only if too long?

#7 2013-03-07 11:53

Re: Count character length, and shorten only if too long?

#8 2013-03-07 12:44

Re: Count character length, and shorten only if too long?

#9 2013-03-08 00:30

Re: Count character length, and shorten only if too long?

#10 2013-03-08 21:05

Re: Count character length, and shorten only if too long?

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