Delete last part

den4b · 2007-12-07 16:35

Expression: (.+)(\.\d+).*
Replace: $1$2

aaa.104.aaa.bbb.ccc.txt         aaa.104.txt
aaa.104.aaa.txt                 aaa.104.txt
aaa.aaa.103.aaa.txt             aaa.aaa.103.txt
aaa.aaa.104.txt                 aaa.aaa.104.txt

Just make sure it satisfies your real files.

ozzii · 2007-12-07 16:45

YES, again.

This is it.

Just a * instead of +
I have try a lot of things but not this.

Thanks Stefan and den4b (creator of this "SO GOOD" software)

den4b · 2007-12-07 16:51

Note the updated expression in the previous post: (.+)(\.\d+).* ... i also put extra "\." in front of the digits, to take into account the very first examples in this topic. This will ensure that the sequence of digits needs a DOT in front of it to be recognized as $2 (second subpattern). So all this patter will do is... strip everything between extension and the last sequence of digits which has a dot in front of them.

Anyway, glad to be of help

ozzii · 2007-12-07 16:55

I saw the new "\."
I was already put it into the old rule (from Stefan), for the exact reason that you say.
This is why the difference was just the "*"

Thanks again both of you. Really big help.

Stefan · 2007-12-07 21:47

Good good! Ozzii mastered the RegEx go ahead Ozzii, go!

Hi Denis, take your time and think about real life and x-mas. All the best for you (all)

Stefan

den4b Forum

#11 2007-12-07 16:35

Re: Delete last part

#12 2007-12-07 16:45

Re: Delete last part

#13 2007-12-07 16:51

Re: Delete last part

#14 2007-12-07 16:55

Re: Delete last part

#15 2007-12-07 21:47

Re: Delete last part

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