Regex match before / after year? e.g. 1994 > (1994)

maryrabbit · 2020-05-27 15:11

Example, adding parenthesis to before and after the matching year pattern / `\d{4}`:

Name:
Batman 1994
Superman (2003)

New Name:
Batman (1994)
Superman (2003)

I tried positive lookahead/behind but reNamer throws unrecognized modifier error

Stefan · 2020-05-27 16:15

Hello and welcome.

The most simplest way is to add parenthesis to all years, if have parenthesis already or not,

to change doubled parenthesis by single one:

Find: ((*|*))
Replace: (*|*)

- - -

Right now no lookaround implemented.

- - -

You could use a "must no match" expression [^...]

FROM:
Batman 1994
Superman (2003)

TO:
Batman (1994)
Superman (2003)

USE:
Regular Expressions:
Expression: "[^(](\d{4})[^)]"
Replace: " ($1)"
[x] skip extension

den4b · 2020-05-27 16:18

The following two rules should do the job:

1) Regular Expressions: Replace expression "\b(\d{4})\b" with "($1)"
2) Replace: Replace all "((" with "(", "))" with ")"

eR@SeR · 2020-05-27 18:04

Or you can use one rule:

1) Regular Expressions: Replace expression "$?(\d{4})$?" with "($1)" (skip extension)

maryrabbit · 2020-05-29 11:56

It works! thank you @stefan @den4b @eR@SeR !!!

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